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	<title>Comments on: One of the Oldest Math Tricks</title>
	<atom:link href="http://mathtricks.org/math-tricks/one-of-the-oldest-math-tricks/feed/" rel="self" type="application/rss+xml" />
	<link>http://mathtricks.org/math-tricks/one-of-the-oldest-math-tricks/</link>
	<description>Math Tricks - Making Math Fun!</description>
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		<title>By: masaru shinoda</title>
		<link>http://mathtricks.org/math-tricks/one-of-the-oldest-math-tricks/comment-page-1/#comment-51</link>
		<dc:creator>masaru shinoda</dc:creator>
		<pubDate>Tue, 09 Mar 2010 15:46:23 +0000</pubDate>
		<guid isPermaLink="false">http://mathtricks.org/?p=208#comment-51</guid>
		<description>ahahahahaha.. it&#039;s a nice trick.. ^_^v

if A=B

so, A-B = 0 right.?

therefore:   =&gt;    (A+B)(A-B) = A(A-B)

             =&gt;    (A+B)(A-B) = A(A-B)  
                    --------     ----
                      (A-B)      (A-B)

             =&gt;   Let us A=2 and B=1; therefore; (A-B) is (2-1)
             =&gt;    so the A-B = 0

             =&gt;   the solution must be undefine...




................................♣cUtEmAntsAnG♣..................</description>
		<content:encoded><![CDATA[<p>ahahahahaha.. it&#8217;s a nice trick.. ^_^v</p>
<p>if A=B</p>
<p>so, A-B = 0 right.?</p>
<p>therefore:   =&gt;    (A+B)(A-B) = A(A-B)</p>
<p>             =&gt;    (A+B)(A-B) = A(A-B)<br />
                    &#8212;&#8212;&#8211;     &#8212;-<br />
                      (A-B)      (A-B)</p>
<p>             =&gt;   Let us A=2 and B=1; therefore; (A-B) is (2-1)<br />
             =&gt;    so the A-B = 0</p>
<p>             =&gt;   the solution must be undefine&#8230;</p>
<p>&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;..♣cUtEmAntsAnG♣&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;</p>
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	<item>
		<title>By: Ryan</title>
		<link>http://mathtricks.org/math-tricks/one-of-the-oldest-math-tricks/comment-page-1/#comment-41</link>
		<dc:creator>Ryan</dc:creator>
		<pubDate>Wed, 10 Feb 2010 13:51:52 +0000</pubDate>
		<guid isPermaLink="false">http://mathtricks.org/?p=208#comment-41</guid>
		<description>don&#039;t call it a proof. it&#039;s not a proof.</description>
		<content:encoded><![CDATA[<p>don&#8217;t call it a proof. it&#8217;s not a proof.</p>
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	<item>
		<title>By: mike</title>
		<link>http://mathtricks.org/math-tricks/one-of-the-oldest-math-tricks/comment-page-1/#comment-40</link>
		<dc:creator>mike</dc:creator>
		<pubDate>Tue, 09 Feb 2010 13:19:51 +0000</pubDate>
		<guid isPermaLink="false">http://mathtricks.org/?p=208#comment-40</guid>
		<description>as said a-b never cancelled bcoz a-b=0 and 0 never cancels other 0</description>
		<content:encoded><![CDATA[<p>as said a-b never cancelled bcoz a-b=0 and 0 never cancels other 0</p>
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	<item>
		<title>By: Marco</title>
		<link>http://mathtricks.org/math-tricks/one-of-the-oldest-math-tricks/comment-page-1/#comment-39</link>
		<dc:creator>Marco</dc:creator>
		<pubDate>Tue, 19 Jan 2010 14:09:50 +0000</pubDate>
		<guid isPermaLink="false">http://mathtricks.org/?p=208#comment-39</guid>
		<description>By the first line: A=B =&gt; A-B=0

...
(A+B)(A-B) = A(A-B)

You can&#039;t divide by (A-B), you can&#039;t divide by 0!</description>
		<content:encoded><![CDATA[<p>By the first line: A=B =&gt; A-B=0</p>
<p>&#8230;<br />
(A+B)(A-B) = A(A-B)</p>
<p>You can&#8217;t divide by (A-B), you can&#8217;t divide by 0!</p>
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